Verifying an Alien Dictionary
Problem Description​
In an alien language, surprisingly, they also use English lowercase letters, but possibly in a different order. The order of the alphabet is some permutation of lowercase letters.
Given a sequence of words written in the alien language, and the order of the alphabet, return true if and only if the given words are sorted lexicographically in this alien language.
Examples​
Example 1:
Input: words = ["hello","leetcode"], order = "hlabcdefgijkmnopqrstuvwxyz"
Output: true
Explanation: As 'h' comes before 'l' in this language, then the sequence is sorted.
Example 2:
Input: words = ["word","world","row"], order = "worldabcefghijkmnpqstuvxyz"
Output: false
Explanation: As 'd' comes after 'l' in this language, then words[0] > words[1], hence the sequence is unsorted.
Example 3:
Input: words = ["apple","app"], order = "abcdefghijklmnopqrstuvwxyz"
Output: false
Explanation: The first three characters "app" match, and the second string is shorter (in size.) According to lexicographical rules "apple" > "app", because 'l' > '∅', where '∅' is defined as the blank character which is less than any other character (More info).
Constraints​
1 <= words.length <= 100
1 <= words[i].length <= 20
order.length == 26
All characters in words[i] and order are English lowercase letters.
Solution​
Python​
class Solution:
def isAlienSorted(self, words: List[str], order: str) -> bool:
order_index = {char: index for index, char in enumerate(order)}
for i in range(len(words) - 1):
for j in range(len(words[i])):
if j >= len(words[i + 1]):
return False
if words[i][j] != words[i + 1][j]:
if order_index[words[i][j]] > order_index[words[i + 1][j]]:
return False
break
return True
# Example usage:
solution = Solution()
print(solution.isAlienSorted(["hello","leetcode"], "hlabcdefgijkmnopqrstuvwxyz")) # Output: true
C++​
#include <vector>
#include <string>
#include <unordered_map>
using namespace std;
class Solution {
public:
bool isAlienSorted(vector<string>& words, string order) {
unordered_map<char, int> order_index;
for (int i = 0; i < order.size(); ++i) {
order_index[order[i]] = i;
}
for (int i = 0; i < words.size() - 1; ++i) {
if (!compare(words[i], words[i + 1], order_index)) {
return false;
}
}
return true;
}
private:
bool compare(const string& word1, const string& word2, unordered_map<char, int>& order_index) {
int len = min(word1.size(), word2.size());
for (int i = 0; i < len; ++i) {
if (word1[i] != word2[i]) {
return order_index[word1[i]] < order_index[word2[i]];
}
}
return word1.size() <= word2.size();
}
};
// Example usage:
int main() {
Solution solution;
vector<string> words = {"hello","leetcode"};
string order = "hlabcdefgijkmnopqrstuvwxyz";
bool result = solution.isAlienSorted(words, order); // Output: true
cout << result << endl;
return 0;
}
Java​
import java.util.HashMap;
import java.util.Map;
class Solution {
public boolean isAlienSorted(String[] words, String order) {
Map<Character, Integer> orderIndex = new HashMap<>();
for (int i = 0; i < order.length(); ++i) {
orderIndex.put(order.charAt(i), i);
}
for (int i = 0; i < words.length - 1; ++i) {
if (!compare(words[i], words[i + 1], orderIndex)) {
return false;
}
}
return true;
}
private boolean compare(String word1, String word2, Map<Character, Integer> orderIndex) {
int len = Math.min(word1.length(), word2.length());
for (int i = 0; i < len; ++i) {
if (word1.charAt(i) != word2.charAt(i)) {
return orderIndex.get(word1.charAt(i)) < orderIndex.get(word2.charAt(i));
}
}
return word1.length() <= word2.length;
}
public static void main(String[] args) {
Solution solution = new Solution();
String[] words = {"hello","leetcode"};
String order = "hlabcdefgijkmnopqrstuvwxyz";
boolean result = solution.isAlienSorted(words, order); // Output: true
System.out.println(result);
}
}
JavaScript​
var isAlienSorted = function (words, order) {
const orderIndex = new Map();
for (let i = 0; i < order.length; ++i) {
orderIndex.set(order[i], i);
}
for (let i = 0; i < words.length - 1; ++i) {
if (!compare(words[i], words[i + 1], orderIndex)) {
return false;
}
}
return true;
function compare(word1, word2, orderIndex) {
const len = Math.min(word1.length, word2.length);
for (let i = 0; i < len; ++i) {
if (word1[i] !== word2[i]) {
return orderIndex.get(word1[i]) < orderIndex.get(word2[i]);
}
}
return word1.length <= word2.length;
}
};
// Example usage:
console.log(isAlienSorted(["hello", "leetcode"], "hlabcdefgijkmnopqrstuvwxyz")); // Output: true