Strictly Palindromic Number
Problem Statement​
An integer n
is strictly palindromic if, for every base b
between 2 and n - 2
(inclusive), the string representation of the integer n
in base b
is palindromic.
Given an integer n
, return true
if n
is strictly palindromic and false
otherwise.
A string is palindromic if it reads the same forward and backward.
Example 1:
Input: n = 9
Output: false
Explanation:
In base 2: 9 = 1001 (base 2), which is palindromic.
In base 3: 9 = 100 (base 3), which is not palindromic.
Therefore, 9 is not strictly palindromic so we return false.
Note that in bases 4, 5, 6, and 7, n = 9 is also not palindromic.
Example 2:
Input: n = 4
Output: false
Explanation:
We only consider base 2: 4 = 100 (base 2), which is not palindromic.
Therefore, we return false.
Constraints:
4 <= n <= 10^5
Solutions​
Intuition​
To determine if a number n
is strictly palindromic, we need to check its representation in all bases from 2 to n - 2
. If any representation is not palindromic, then n
is not strictly palindromic.
Approach​
-
Check Base Representation:
- Convert the number
n
to each base from 2 ton - 2
. - Check if the representation in each base is palindromic.
- Convert the number
-
Early Termination:
- If any base representation is not palindromic, return
false
.
- If any base representation is not palindromic, return
Java​
class Solution {
public boolean isStrictlyPalindromic(int n) {
return false;
}
}
Python​
class Solution:
def isStrictlyPalindromic(self, n: int) -> bool:
return False
Conclusion​
For the given problem constraints, the function always returns false. This is because it's mathematically impossible for any number greater than 4 to be strictly palindromic according to the given definition.