Replace All 0's with 5

Problem

Given a number N. The task is to complete the function convertFive() which replaces all zeros in the number with 5 and returns the number.

Examples:

Example 1:

Input
2
1004
121

Output
1554
121

Explanation:
Testcase 1:  At index 1 and 2 there is 0 so we replace it with 5.
Testcase 2: There is no,0 so output will remain the same.

Input:

The first line of input contains an integer T, denoting the number of test cases. Then T test cases follow. Each test case contains a single integer N denoting the number.

Output:

The function will return an integer where all zero's are converted to 5.

Your task:

Since this is a functional problem you don't have to worry about input, you just have to complete the function convertFive().

Constraints:

• $1 <= T <= 10^3$
• $1 <= N <= 10^4$

Solution

Python

def convertFive(self,n):
    num_str = str(n)
    result = ""
    for char in num_str:
        if char == '0':
            result += '5'
        else:
            result += char
    return int(result)

Java

public static int convertFive(int n){
    String numStr = String.valueOf(n);
    StringBuilder result = new StringBuilder();
    for (int i = 0; i < numStr.length(); i++) {
        char currentChar = numStr.charAt(i);
        if (currentChar == '0') {
            result.append('5');
        }
        else {
            result.append(currentChar);
        }
    }
    int convertedNumber = Integer.parseInt(result.toString());
    return convertedNumber;
}

C++

int convertFive(int n) {
    string numStr = to_string(n);
    for (char &c : numStr) {
        if (c == '0') {
            c = '5';
        }
    }
    int convertedNumber = stoi(numStr);
    return convertedNumber;
}

C

int convertFive(int n) {
    int result = 0;
    int position = 1;
    while (n != 0) {
        int digit = n % 10;
        if (digit == 0) {
            result += 5 * position;
        }
        else {
            result += digit * position;
        }
        n /= 10;
        position *= 10;
    }
    return result;
}