Leap Year

Problem

For an input year N, find whether the year is a leap or not.

Examples:

Example 1:

Input:
N = 4
Output:
1
Explanation:
4 is not divisible by 100 and is divisible by 4 so its a leap year

Example 2:

Input:
N = 2021
Output:
0
Explanation:
2021 is not divisible by 100 and is also not divisible by 4 so its not a leap year

Your task:

You don't need to read input or print anything. Your task is to complete the function isLeap() which takes an integer N as input parameter and returns 1 if N is a leap year and 0 otherwise.

• Expected Time Complexity: $O(1)$
• Expected Auxiliary Space: $O(1)$

Constraints:

• $1<=N<=9999$

Solution

Python

def isLeap (self, N):
    if((N % 400 == 0) or (N % 100 != 0) and (N % 4 == 0)): 
        return 1
    else:
        return 0

Java

static int isLeap(int N){
    if((N % 400 == 0) || (N % 100 != 0) && (N % 4 == 0))
        return 1;
    else
        return 0;
}

C++

int isLeap(int N){
    if((N % 400 == 0) || (N % 100 != 0) && (N % 4 == 0))
        return 1;
    else
        return 0;
}

C

int isLeap(int N){
    if((N % 400 == 0) || (N % 100 != 0) && (N % 4 == 0))
        return 1;
    else
        return 0;
}

• Time Complexity: $O(1)$
• Auxiliary Space: $O(1)$