Skip to main content

Kids With the Greatest Number of Candies

Problem Statement​

There are n kids with candies. You are given an integer array candies, where each candies[i] represents the number of candies the ith kid has, and an integer extraCandies, denoting the number of extra candies that you have.

Return a boolean array result of length n, where result[i] is true if, after giving the ith kid all the extraCandies, they will have the greatest number of candies among all the kids, or false otherwise.

Example 1:

Input: candies = [2,3,5,1,3], extraCandies = 3

Output: [true,true,true,false,true]

Explanation: If you give all extraCandies to:

  • Kid 1, they will have 2 + 3 = 5 candies, which is the greatest among the kids.
  • Kid 2, they will have 3 + 3 = 6 candies, which is the greatest among the kids.
  • Kid 3, they will have 5 + 3 = 8 candies, which is the greatest among the kids.
  • Kid 4, they will have 1 + 3 = 4 candies, which is not the greatest among the kids.
  • Kid 5, they will have 3 + 3 = 6 candies, which is the greatest among the kids.

Example 2:

Input: candies = [4,2,1,1,2], extraCandies = 1

Output: [true,false,false,false,false]

Explanation: There is only 1 extra candy. Kid 1 will always have the greatest number of candies, even if a different kid is given the extra candy.

Example 3:

Input: candies = [12,1,12], extraCandies = 10

Output: [true,false,true]

Constraints:

  • n == candies.length
  • 2 <= n <= 100
  • 1 <= candies[i] <= 100
  • 1 <= extraCandies <= 50

Solutions​

Approach​

To determine if each kid can have the greatest number of candies after receiving extraCandies, follow these steps:

  1. Find the Maximum Candies:

    • Traverse through the candies array to find the maximum number of candies any kid currently has.

  2. Check Each Kid's Condition:

    • Iterate through the candies array again.
    • For each kid, check if adding extraCandies to their current candies makes their total candies equal to or greater than the maximum number found.
    • Store true if the condition is met, otherwise store false.

Java​


class Solution {
    public List<Boolean> kidsWithCandies(int[] candies, int extraCandies) {
        int maxCandies = 0;
        for (int candy : candies) {
            maxCandies = Math.max(maxCandies, candy);
        }
        
        List<Boolean> result = new ArrayList<>();
        for (int candy : candies) {
            result.add(candy + extraCandies >= maxCandies);
        }
        
        return result;
    }

}

Python​

class Solution:
    def kidsWithCandies(self, candies: List[int], extraCandies: int) -> List[bool]:
        maxCandies = max(candies)
        result = []
        
        for candy in candies:
            result.append(candy + extraCandies >= maxCandies)
        
        return result